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4024/12 Oct/Nov 2021, Question 12: Similar Triangles

Cambridge O Level Mathematics 4024 · Paper 12 (Non-calculator) · Non-calculator · 3 marks

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The question, in short

Using the rectangle ABCD with E on diagonal AC and angle DEC = 90°, prove triangle ADC is similar to triangle DEC, justifying each statement.

Summarised in our own words. Use the official paper for the exact wording and the diagram.

Solution · 3 marks

  1. 1Angle ACD = angle DCE (common/shared angle at C)
  2. 2Angle ADC = angle DEC = 90° (ADC is an angle of the rectangle, DEC given)
  3. 3Angle DAC = angle EDC (third angles in a triangle, since angles add to 180°)
  4. 4All three pairs of angles are equal, so triangle ADC is similar to triangle DEC

Answerangle ACD = angle DCE, shared angle; angle ADC = angle DEC = 90°, given; angle DAC = angle EDC, third angles in a triangle; three angles equal, therefore the triangles are similar

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