4024/22 Oct/Nov 2024, Question 2: Estimating the Mean for Grouped Data
Cambridge O Level Mathematics 4024 · Paper 22 (Calculator) · Calculator · 10 marks
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The question, in short
Use a table of 10 cars' ages and values to plot points, fit a line, estimate a value at 7 years, and judge extrapolation to 12 years.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Plot the four remaining age-value pairs from the table onto the given scatter diagram.
- 1Plot (5, 4500), (6, 3000), (8, 1500) and (8, 2000)
Answer4 points plotted correctly
Part (aii) · 1 mark
Add a straight line of best fit through the plotted points.
- 1Rule a straight line with negative gradient through the middle of the points, e.g. through the mean point (5.1, 3860)
AnswerRuled line of best fit
Part (aiii) · 1 mark
Read off the line the estimated value for a 7-year-old car.
- 1Go up from age 7 to the line and read across to the value axis
- 2Value ≈ $2400
Answer2400 (accept 2100 to 2700)
Part (aiv) · 1 mark
Explain why the diagram cannot reliably estimate a 12-year-old car's value.
- 112 years is outside the range of the data (ages 3 to 8), so the line would be extrapolated and may even give a negative value
AnswerOutside range of data OR 12 would give a negative value (which is impossible) OR The line of best fit does not go as far as 12
Part (bi) · 1 mark
Work out the fraction of 50 cars travelling over 50 000 km, simplified.
- 1More than 50 000 km: 11 + 17 = 28 cars
- 228/50 = 14/25
Answer14/25
Part (bii) · 1 mark
Identify which distance interval holds the median for the 50 cars.
- 1Median is the 25th/26th value; cumulative totals 8, 22, 33, 50
- 2Median interval: 50 < d ≤ 60
Answer50 < d ≤ 60
Part (biii) · 3 marks
Estimate the mean distance using the grouped frequency table's midpoints.
- 1Midpoints 25, 45, 55, 80
- 2Σfx = 8 × 25 + 14 × 45 + 11 × 55 + 17 × 80 = 200 + 630 + 605 + 1360 = 2795
- 3Mean = 2795 ÷ 50 = 55.9 thousand km
Answer55.9
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