4MA1/1F Jun 2019, Question 16: Substitution
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1F (Foundation) · Calculator · 8 marks
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The question, in short
Five short algebra tasks: evaluate a formula, simplify two index expressions, expand a pair of brackets, and factorise an expression fully.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 2 marks
Substitute g = 7 and h = −4 into P = 2g + 3h and work out P.
- 12 × 7 = 14
- 23 × −4 = −12
- 314 + (−12) = 2
Answer2
Part (b) · 1 mark
Simplify e⁹ ÷ e⁵ as a single power of e.
- 1Subtract the powers: e⁹ ÷ e⁵ = e⁹⁻⁵ = e⁴
Answere⁴
Part (c) · 1 mark
Simplify (y²)⁸ as a single power of y.
- 1Multiply the powers: (y²)⁸ = y²ˣ⁸ = y¹⁶
Answery¹⁶
Part (d) · 2 marks
Expand and simplify (x + 9)(x − 2).
- 1(x + 9)(x − 2) = x² − 2x + 9x − 18
- 2x² + 7x − 18
Answerx² + 7x − 18
Part (e) · 2 marks
Factorise 16c⁴p² + 20cp³ fully.
- 1The highest common factor of both terms is 4cp²
- 216c⁴p² = 4cp² × 4c³ and 20cp³ = 4cp² × 5p
- 34cp²(4c³ + 5p)
Answer4cp²(4c³ + 5p)
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