4MA1/2H Jun 2021, Question 5: Angles in Parallel Lines
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 2H (Higher) · Calculator · 5 marks
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The question, in short
Using parallel lines ABCD and FGHI with transversals EBGJ and ECH, BE = CE and angle BEC = 44°, find angle JGH, justifying each step.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 5 marks
- 1BE = CE, so triangle BEC is isosceles: angle EBC = (180 − 44) ÷ 2 = 68°
- 2Angles on a straight line: angle CBG = 180 − 68 = 112°
- 3ABCD and FGHI are parallel, so angle JGH = angle CBG (corresponding angles)
- 4Angle JGH = 112
Answer112
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