4MA1/1H Jun 2023, Question 6: Index Laws with Letters
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1H (Higher) · Calculator · 8 marks
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The question, in short
Simplify a cubed product of powers, evaluate an expression with a zero index, factorise two expressions fully, and factorise then solve a quadratic.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 2 marks
Simplify (2c⁴d⁷)³, giving the result in its simplest index form.
- 1Cube each part: 2³ = 8
- 2(c⁴)³ = c¹² and (d⁷)³ = d²¹ (multiply the powers)
- 38c¹²d²¹
Answer8c¹²d²¹
Part (b) · 1 mark
Work out the value of 5y⁰ given that y is greater than 0.
- 1Any non-zero number to the power 0 is 1, so y⁰ = 1
- 25 × 1 = 5
Answer5
Part (c) · 2 marks
Factorise 16a²b³ + 20a³b completely.
- 1Find common factor: 4a²b
- 216a²b³ ÷ 4a²b = 4b²
- 320a³b ÷ 4a²b = 5a
- 44a²b(4b² + 5a)
Answer4a²b(4b² + 5a)
Part (di) · 2 marks
Factorise the quadratic expression x² + 9x − 22.
- 1Look for two numbers that multiply to −22 and add to 9: 11 and −2
- 2(x + 11)(x − 2)
Answer(x + 11)(x − 2)
Part (dii) · 1 mark
Using your factorisation, solve x² + 9x − 22 = 0.
- 1(x + 11)(x − 2) = 0
- 2x + 11 = 0 → x = −11
- 3x − 2 = 0 → x = 2
- 4−11, 2
Answer−11, 2
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