0580/22 May/Jun 2024, Question 22: Trigonometric Graphs and Equations
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 7 marks
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The question, in short
Identify the function type for two sketched curves, then sketch y = sin x over 0° to 360° and solve sin x + 0.4 = 0 in that range.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 1 mark
Choose which function type matches the first curve by ringing the correct option.
- 1The curve has the S-shape of y = x³, so it is cubic
Answercubic
Part (aii) · 1 mark
Choose which function type matches the second curve by ringing the correct option.
- 1Two separate branches that approach the axes but never meet them: reciprocal
Answerreciprocal
Part (bi) · 2 marks
Draw the graph of y = sin x on the grid for x from 0° to 360°.
- 1Start at (0, 0), rise to a maximum of 1 at 90°
- 2Fall through (180, 0) to a minimum of −1 at 270°
- 3Rise back to (360, 0) with a smooth wave shape
Answercorrect sine curve sketch through (0, 0), (180, 0) and (360, 0)
Part (bii) · 3 marks
Find the values of x between 0° and 360° satisfying sin x + 0.4 = 0.
- 1sin x = −0.4
- 2sin⁻¹(0.4) = 23.57…°
- 3x = 180 + 23.58 = 203.6° or x = 360 − 23.58 = 336.4°
Answer203.6 and 336.4
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Also searched as: 0580/22/M/J/24 · 0580_s24_qp_22 · 0580 s24 22 · question 22.
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