0580/22 Oct/Nov 2021, Question 12: Pattern Sequences and Special Sequences
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 5 marks
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The question, in short
Complete the table by finding the nth term expression for each of sequences A, B and C from their first five terms.
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Solution · 5 marks
- 1A: terms go down by 5, so −5n; 1st term 8 = −5 + 13
- 2A: nth term = 13 − 5n
- 3B: numerators 2, 3, 4, … = n + 1; denominators 1, 2, 3, … = n
- 4B: nth term = (n + 1)/n
- 5C: terms double each time: 1/2 = 2⁻¹, 1 = 2⁰, 2 = 2¹, …
- 6C: nth term = 2ⁿ⁻²
AnswerSequence A: 13 − 5n Sequence B: (n + 1)/n Sequence C: 2ⁿ⁻²
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Also searched as: 0580/22/O/N/21 · 0580_w21_qp_22 · 0580 w21 22 · question 12.
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