0580/22 Oct/Nov 2021, Question 11: Speed-Time Graphs and Acceleration
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 3 marks
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The question, in short
Complete a speed–time graph for a car that accelerates at 0.7 m/s² for 20 s to 14 m/s, cruises 210 m, then decelerates at 1.4 m/s² to rest.
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Solution · 3 marks
- 1Time at 14 m/s = 210 ÷ 14 = 15 s, so constant speed from t = 20 to t = 35
- 2Draw a horizontal line from (20, 14) to (35, 14)
- 3Time to stop = 14 ÷ 1.4 = 10 s, so the car stops at t = 35 + 10 = 45
- 4Draw a straight line from (35, 14) to (45, 0)
AnswerStraight line from (20, 14) to (35, 14) and straight line from (35, 14) to (45, 0)
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Also searched as: 0580/22/O/N/21 · 0580_w21_qp_22 · 0580 w21 22 · question 11.
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