0580/23 Oct/Nov 2021, Question 24: Trigonometric Graphs and Equations
Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Calculator · 2 marks
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The question, in short
Solve tan x = √3 for all x in the interval 0° ≤ x ≤ 360°, giving every possible value of x.
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Solution · 2 marks
- 1tan⁻¹(√3) = 60°
- 2tan repeats every 180°: 60 + 180 = 240°
- 3x = 60° and x = 240°
Answer60 and 240
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