0580/43 Oct/Nov 2021, Question 8: Estimating the Mean for Grouped Data
Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 15 marks
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The question, in short
Statistics: pie chart for 600 people, a box plot from five summary values, range, mode and median from a dice table, and an estimated mean from grouped times.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 1 mark
Use the 60° tennis sector to show it is 100 people.
- 1Tennis = 60/360 × 600 = 100 people
Answer60/360 × 600
Part (aii) · 2 marks
People choosing rugby from a 27° sector.
- 1Rugby = 27/360 × 600 = 45 people
Answer45
Part (aiii) · 2 marks
Add cricket (125 people) and swimming to the pie chart.
- 1Cricket angle = 125/600 × 360 = 75°
- 2Swimming angle = 360 − 105 − 60 − 27 − 75 = 93°
- 3Rule a line from the centre to split the remaining space into 75° (cricket) and 93° (swimming)
AnswerCorrect straight line on the pie chart
Part (b) · 3 marks
Draw a box plot from smallest 0.6, range 8.1, median 5.2, LQ 3.4, IQR 4.1.
- 1Upper quartile = 3.4 + 4.1 = 7.5; largest = 0.6 + 8.1 = 8.7
- 2Draw the box from 3.4 to 7.5 with a line at the median 5.2
- 3Draw whiskers from 0.6 to 3.4 and from 7.5 to 8.7
AnswerCorrect diagram: 0.6, 3.4, 5.2, 7.5, 8.7
Part (ci) · 1 mark
Range of the dice scores.
- 1Range = 6 − 1 = 5
Answer5
Part (cii) · 1 mark
Modal score.
- 1Highest frequency is 25, so mode = 2
Answer2
Part (ciii) · 1 mark
Median of 100 rolls.
- 1Median is between the 50th and 51st scores
- 2Cumulative frequencies: 16, 41, 58, so both are 3
- 3Median = 3
Answer3
Part (d) · 4 marks
Estimate the mean time from five class intervals using midpoints.
- 1Mid-values: 15, 22.5, 27.5, 40, 65
- 2Σfx = 2×15 + 8×22.5 + 12×27.5 + 16×40 + 12×65
- 3= 30 + 180 + 330 + 640 + 780 = 1960
- 4Mean = 1960 ÷ 50 = 39.2 seconds
Answer39.2
Stuck on a step? Read the free lesson: Estimating the Mean for Grouped Data
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Also searched as: 0580/43/O/N/21 · 0580_w21_qp_43 · 0580 w21 43 · question 8.
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