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0580/21 Oct/Nov 2022, Question 13: Area Under a Speed-Time Graph

Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Calculator · 3 marks

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The question, in short

Speed–time graph for a car's first 15 seconds: rising from 0 to 14 m/s over 5 s, then constant at 14 m/s. Find the initial acceleration and the total distance travelled.

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Part (a) · 1 mark

Find the car's acceleration over the first 5 seconds from the graph.

  1. 1Acceleration = gradient = 14 ÷ 5
  2. 2= 2.8 m/s²

Answer2.8

Part (b) · 2 marks

Find the total distance travelled in the 15 seconds.

  1. 1Distance = area under graph
  2. 2Triangle: 1/2 × 5 × 14 = 35
  3. 3Rectangle: (15 − 5) × 14 = 140
  4. 4Total = 35 + 140 = 175 m

Answer175

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Also searched as: 0580/21/O/N/22 · 0580_w22_qp_21 · 0580 w22 21 · question 13.
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