0580/22 Oct/Nov 2023, Question 20: Upper and Lower Bounds
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 3 marks
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The question, in short
Rectangle area 55.2 cm² to 1 d.p., length 9 cm to nearest cm. Find the upper bound of the width.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 3 marks
- 1Upper bound of area = 55.2 + 0.05 = 55.25
- 2Lower bound of length = 9 − 0.5 = 8.5
- 3Upper bound of width = 55.25 ÷ 8.5 = 6.5 cm
Answer6.5
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Also searched as: 0580/22/O/N/23 · 0580_w23_qp_22 · 0580 w23 22 · question 20.
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