0580/33 Oct/Nov 2023, Question 5: Mean, Median, Mode and Range
Cambridge IGCSE Mathematics 0580 · Paper 33 (Core) · Calculator · 12 marks
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The question, in short
Zena records daily letter counts, posts parcels, converts currency, finds a percentage increase, and works with a cuboid parcel net and volume.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 1 mark
From the 12 daily letter counts, state the most frequent value.
- 17 appears three times, more than any other value: mode = 7
Answer7
Part (aii) · 2 marks
Find the middle value of the 12 ordered letter counts.
- 1In order: 0, 1, 1, 2, 3, 3, 5, 6, 7, 7, 7, 8
- 2The middle values (6th and 7th) are 3 and 5
- 3Median = (3 + 5) ÷ 2 = 4
Answer4
Part (b) · 3 marks
Using the lightest 4.6 kg, heaviest 6.2 kg and mean 5.01 kg of the other four, find the mean of all 6 parcels.
- 1Total of the other 4 = 4 × 5.01 = 20.04 kg
- 2Total of all 6 = 20.04 + 4.6 + 6.2 = 30.84 kg
- 3Mean = 30.84 ÷ 6 = 5.14 kg
Answer5.14
Part (c) · 1 mark
Convert 105 euros to dollars using $1 = 0.84 euros.
- 1105 ÷ 0.84 = $125
Answer125
Part (d) · 2 marks
Find the percentage increase from $22.68 to $44.
- 1Increase = 44 − 22.68 = 21.32
- 221.32/22.68 × 100 = 94.00…%
- 3≈ 94%
Answer94 or 94.00…
Part (ei) · 2 marks
On the 1 cm² grid, complete the net of the 6 cm by 2 cm by 3 cm cuboid, two faces already drawn.
- 1The faces are two 3 × 6, two 2 × 6 and two 3 × 2 rectangles
- 2Below the 3 × 6 face draw a 3 × 2 face, then another 3 × 6 face (same 3 cm column)
- 3Attach a 2 × 6 rectangle to the left and to the right of the given 3 × 6 face
AnswerFully correct net
Part (eii) · 1 mark
Calculate the volume of the 6 cm by 2 cm by 3 cm cuboid.
- 1Volume = 6 × 2 × 3 = 36 cm³
Answer36
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Also searched as: 0580/33/O/N/23 · 0580_w23_qp_33 · 0580 w23 33 · question 5.
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