0580/21 Oct/Nov 2024, Question 21: Trigonometric Graphs and Equations
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Calculator · 3 marks
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The question, in short
Solve 3 tan x + 5 = 1 for x in the interval 0° to 360°, giving all solutions.
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Solution · 3 marks
- 13 tan x = 1 − 5 = −4 → tan x = −4/3
- 2tan⁻¹(4/3) = 53.13…°, and tan is negative in the 2nd and 4th quadrants
- 3x = 180 − 53.13… = 126.9° and x = 360 − 53.13… = 306.9°
Answer126.9 and 306.9
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