4024/11 May/Jun 2021, Question 25: Perpendicular Lines
Cambridge O Level Mathematics 4024 · Paper 11 (Non-calculator) · Non-calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Circle centre C (0, 1) with P (3, 5) on its circumference; find the equation of the tangent to the circle at P.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 4 marks
- 1Gradient CP = (5 − 1)/(3 − 0) = 4/3
- 2Tangent is perpendicular to CP: gradient = −3/4
- 3y − 5 = −3/4(x − 3)
- 44y − 20 = −3x + 9
- 54y + 3x = 29
Answer4y + 3x = 29
Stuck on a step? Read the free lesson: Perpendicular Lines
Practise more perpendicular lines questions
Real 4024 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on perpendicular lines
Also searched as: 4024/11/M/J/21 · 4024_s21_qp_11 · 4024 s21 11 · question 25.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.