Lemmara logoLemmaraWorked solution

4024/13 May/Jun 2025, Question 18: Speed-Time Graphs and Acceleration

Cambridge O Level Mathematics 4024 · Paper 13 (Non-calculator) · Non-calculator · 5 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

Using a speed–time graph for a car over 90 seconds, find the unknown speed V from a total distance of 1.01 km, then find the deceleration over the final 20 seconds.

Summarised in our own words. Use the official paper for the exact wording and the diagram.

Part (a) · 4 marks

The car covers 1.01 km in 90 seconds; use the graph's three sections to calculate the value of V.

  1. 1Distance = area under graph; 1.01 km = 1010 m
  2. 2Area = 1/2 × 30 × (24 − V) + 70V + 1/2 × 20 × V
  3. 3= 360 − 15V + 70V + 10V = 360 + 65V
  4. 4360 + 65V = 1010
  5. 565V = 650, V = 10

Answer10

Part (b) · 1 mark

Given V = 10, the speed falls from V m/s at 70 s to 0 at 90 s; calculate the deceleration.

  1. 1From part (a), V = 10 m/s
  2. 2Speed falls from 10 to 0 between t = 70 and t = 90, which is 20 seconds
  3. 3Deceleration = 10 ÷ 20 = 0.5 m/s²

Answer0.5

Stuck on a step? Read the free lesson: Speed-Time Graphs and Acceleration

Practise more speed-time graphs and acceleration questions

Real 4024 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on speed-time graphs and acceleration

Also searched as: 4024/13/M/J/25 · 4024_s25_qp_13 · 4024 s25 13 · question 18.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.