4024/12 Oct/Nov 2023, Question 22: Removed from the 2025–27 syllabuses (parked)
Cambridge O Level Mathematics 4024 · Paper 12 (Non-calculator) · Non-calculator · 6 marks
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The question, in short
Given a 2×2 matrix multiplying a column vector to equal another column vector, form equations and use them to derive x² − 3x = 0, solve it, then find y for the positive x.
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Part (a) · 2 marks
Multiply out the matrix and column vector, equate components, and show the resulting equation simplifies to x² − 3x = 0.
- 1Top row: x(x − 1) + 3 × 2 = 2x + 6
- 2x² − x + 6 = 2x + 6
- 3x² − 3x = 0
Answerx² − x + 6 = 2x + 6 leading to x² − 3x = 0
Part (bi) · 2 marks
Solve the quadratic equation x² − 3x = 0 for x.
- 1x(x − 3) = 0
- 2x = 3 or x = 0
Answer3, 0
Part (bii) · 2 marks
Using the positive value of x from part (i), find the corresponding value of y.
- 1x = 3
- 2y = 2(x − 1) + (x + 1) × 2 = 2 × 2 + 4 × 2
- 3y = 12
Answer12
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Also searched as: 4024/12/O/N/23 · 4024_w23_qp_12 · 4024 w23 12 · question 22.
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