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4MA1/1FR Jun 2023, Question 24: Standard Form

Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1FR (Foundation) · Calculator · 3 marks

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The question, in short

Convert a small number in standard form to an ordinary number, then evaluate a fraction of numbers in standard form and give the result in standard form.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (a) · 1 mark

Write 5.6 × 10⁻³ as an ordinary number.

  1. 1A power of 10⁻³ moves the digits three places to the right
  2. 25.6 × 10⁻³ = 0.0056

Answer0.0056

Part (b) · 2 marks

Work out (6 × 10³) ÷ (2.1 × 10⁻⁴ + 9 × 10⁻⁵), giving the answer in standard form.

  1. 1Bottom: 2.1 × 10⁻⁴ = 0.00021 and 9 × 10⁻⁵ = 0.00009
  2. 20.00021 + 0.00009 = 0.0003, which is 3 × 10⁻⁴
  3. 3Top: 6 × 10³ = 6000
  4. 46000 ÷ 0.0003 = 20 000 000
  5. 5In standard form that is 2 × 10⁷

Answer2 × 10⁷

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