4PM1/02 Jan 2022, Question 2: Solving Trig Equations
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 5 marks
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The question, in short
Solve sin(2θ − 20)° − √3 cos(2θ − 20)° = 0 for 0 ≤ θ ≤ 180, giving all values of θ in the range.
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Solution · 5 marks
- 1sin(2θ − 20)° = √3 cos(2θ − 20)°
- 2tan(2θ − 20)° = √3
- 32θ − 20 = 60°, 240°
- 42θ = 80°, 260°
- 5θ = 40°, 130°
Answerθ = 40°, 130°
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