حل السؤال 9، 4MA1/2F يناير 2021: الأحداث المركبة باستخدام الجداول ذات الاتجاهين

1. 1Each score is the spinner number take away the dice number.
2. 2Spinner 7: 7 − 1 = 6, 7 − 2 = 5, 7 − 3 = 4, 7 − 4 = 3, 7 − 5 = 2, 7 − 6 = 1
3. 3Spinner 8: 8 − 1 = 7, 8 − 2 = 6, 8 − 3 = 5, 8 − 4 = 4, 8 − 5 = 3, 8 − 6 = 2
4. 4The completed table reads 5, 4, 3, 2, 1, 0 for spinner 6, then 6, 5, 4, 3, 2, 1 for spinner 7, then 7, 6, 5, 4, 3, 2 for spinner 8.

AnswerSpinner 6 row: 5, 4, 3, 2, 1, 0 (given); spinner 7 row: 6, 5, 4, 3, 2, 1; spinner 8 row: 7, 6, 5, 4, 3, 2

1. 1The table has 3 × 6 = 18 equally likely outcomes.
2. 2The scores that are not less than 6 are 6 (spinner 7, dice 1), 7 (spinner 8, dice 1) and 6 (spinner 8, dice 2), which is 3 outcomes.
3. 3So 18 − 3 = 15 of the outcomes give a score less than 6.
4. 4P(score less than 6) = 15/18 = 5/6

Answer15/18 (= 5/6)

1. 1The odd scores in the table are 5, 3 and 1 in the spinner 6 row, 5, 3 and 1 in the spinner 7 row, and 7, 5 and 3 in the spinner 8 row.
2. 2That is 3 + 3 + 3 = 9 odd scores out of the 18 outcomes.
3. 3P(score is an odd number) = 9/18 = 1/2

Answer9/18 (= 1/2)