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0580/22 May/Jun 2021, Question 23: Trigonometric Graphs and Equations

Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 2 marks

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The question, in short

Solve 4 sin x = 3 for x in the interval 0° ≤ x ≤ 360°, giving all solutions.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Solution · 2 marks

  1. 1sin x = 3/4 = 0.75
  2. 2x = sin⁻¹(0.75) = 48.59… ≈ 48.6°
  3. 3x = 180 − 48.59… = 131.4…° ≈ 131.4°

Answer48.6 or 48.59… and 131.4 or 131.4…

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Also searched as: 0580/22/M/J/21 · 0580_s21_qp_22 · 0580 s21 22 · question 23.
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