حل السؤال 10، 4MA1/1H يناير 2020: إيجاد المناطق من المتباينات المتعددة

1. 1The left-hand boundary is the vertical line x = −1 and the shaded region lies to the right of it, so x ≥ −1
2. 2The sloping boundary at the top right passes through (0, 4) and (4, 0), so its gradient is −1 and its equation is y = 4 − x
3. 3The shaded region lies below that line, so y ≤ 4 − x, which can be written x + y ≤ 4
4. 4The remaining boundary is the given line y = (1/3)x − 2 and the shaded region lies above it, so y ≥ (1/3)x − 2
5. 5The three inequalities are x ≥ −1, x + y ≤ 4 and y ≥ (1/3)x − 2

Answerx ≥ −1, x + y ≤ 4, y ≥ (1/3)x − 2